**Perform calculations to the correct number of significant figures. **

a. 3.10007 x 9.441 x 0.0301 /2.31

.8809596/2.31= .38136779

to round properly you take the quantity with the fewest significant figures which is 3 and round the fourth

=.381

b. Was the same problem as a, is the book messing with us?!

c. 2.5110 x 21.20 / (44.11+1.223)

53.2332/45.333 = 1.1742704

Since the addition problem only had 2 significant figures within the decimal (44.11) there will only be 2 significant figures.

=1.2

d. (12.01 x 0.3) + 4.811

3.603 + 4.811= 8.414

since .3 only had 1 significant figure the answer must be rounded to one significant figure

=8